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d' is equal to |meanA - meanB|/SD when you have two gaussian distributions of equal variance and different means. Imagine SD=1, meanA = 0, meanB = 1, with B>A as the "correct" answer (perhaps B is the signal, and A is the noise). This will give you a d' of 1 because the difference between the means is 1, divided by a standard deviation of 1. The ...

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